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ioan · ‎06-30-2015

Let's say I have this xml:

<madona>
<img src="madonna1.jpg" alt='Foligno Madonna, by Raphael' />
<img src="madonna2.jpg" alt='Madonna' />
<img src="madonna3.jpg" alt='Foligno Madonna, by Raphael' />
<img src="madonna4.jpg" alt='Foligno Madonna, by Raphael' />
</madona>

... and I want to choose an img element at random. Can someone point me in the right direction?

Thanks.

https://github.com/e1ioan/
http://rokucam.com

renojim · ‎06-30-2015

xmlel = CreateObject("roXmlElement")
xmlel.Parse(xml)  ' should check return value
rndimg = xmlel.img[rnd(xmlel.img.Count())-1]
src = rndimg@src
alt = rndimg@alt

-JT

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EnTerr · ‎06-30-2015

Given the example parsed into roXmlElement `xml`:


BrightScript Debugger> choice = rnd(xml.img.count()) - 1    
BrightScript Debugger> ? choice, xml.img[choice]
 2            <Component: roXMLElement>
BrightScript Debugger> ? xml.img[choice].genXML(0)
<img alt="Foligno Madonna, by Raphael" src="madonna3.jpg" />

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Choose a random XML element

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Re: Choose a random XML element